Answer:
Explanation:
Given
radius of internal sphere is [tex]r_a=1.4\ cm[/tex]
radius of Outer sphere is [tex]r_b=9.50\ cm[/tex]
+q is put on the inner sphere and -q charge is put on the outer spherical shell
Potential difference [tex]\Delta V=500\ V[/tex]
Potential difference of two concentric shell is given by
[tex]\Delta V=\frac{kq}{r_a}-\frac{kq_b}{r_b}[/tex]
[tex]\Rightarrow \Delta V=kq\left ( \frac{1}{r_a}-\frac{1}{r_b}\right )[/tex]
[tex]\Rightarrow q=\frac{V}{k\left ( \frac{1}{r_a}-\frac{1}{r_b}\right )}[/tex]
[tex]\Rightarrow q=\frac{500}{9\times 10^9\cdot \left ( \frac{1}{1.4\times 10^{-2}}-\frac{1}{9.5\times 10^{-2}}\right )}[/tex]
[tex]\Rightarrow q=\frac{500}{9\times 10^9\times 100\cdot \left ( 0.6089\right )}[/tex]
[tex]q=9.12\times 10^{-10}\ C[/tex]
