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A(n) 500-Ω and a(n) 2000-Ω resistor are connected in series with a 12-V battery. Part A What is the voltage across the 2000-Ω resistor?

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princessesther2011

Answer:

9.6 V

Explanation:

Total resistance (Rt) = R1 + R2 = 500 + 2000 = 2500 ohm

V = IRt

I = V/Rt = 12/2500 = 4.8×10^-3 A

Voltage across the 2000 ohm resistor (V2) = IR2 = 4.8×10^-3 × 2000 = 9.6 V

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