Respuesta :

transitionstate

Answer:

                      Empirical Formula  =  N₂H₈SO₄   Or    (NH₄)₂SO₄

Explanation:

Step 1: Calculate Moles of each Element;

                     Moles of N  =  %N ÷ At.Mass of N

                     Moles of N  = 21.20 ÷ 14.01

                     Moles of N  =  1.5132 mol

                     Moles of H  =  %H ÷ At.Mass of H

                     Moles of H  = 6.10 ÷ 1.01

                     Moles of H  =  6.0396 mol

                     Moles of S  =  %S ÷ At.Mass of S

                     Moles of S  = 24.20 ÷ 32.06

                     Moles of S  =  0.7548 mol

                     Moles of O  =  %O ÷ At.Mass of O

                     Moles of O  = 48.50 ÷ 16.0

                     Moles of O  =  3.0312 mol

Step 2: Find out mole ratio and simplify it;

               N                                        H                                     S

           1.5132                              6.0396                             0.7548

    1.5132/0.7548                  6.0396/0.7548                 0.7548/0.7548

              2                                        8                                       1

                                                    O

                                                  3.0312

                                           3.0312/0.7548

                                                     4

Result:

       Empirical Formula  =  N₂H₈SO₄   Or    (NH₄)₂SO₄

samueladesida43

The empirical formula of a compound that consists of 21.2%N, 6.1%H, 24.2% S and 48.5% O is N2H8SO4.

HOW TO CALCULATE EMPIRICAL FORMULA:

Empirical formula is the simplest whole number ratio of a compound. The empirical formula of a compound can be calculated as follows:

  1. N - 21.2% = 21.2g
  2. H - 6.1% = 6.1g
  3. S - 24.2% = 24.2g
  4. O = 48.5% = 48.5g

Firstly, we divide each value by the molar mass as follows:

  1. N = 21.2g ÷ 14g/mol = 1.51mol
  2. H = 6.1g ÷ 1g/mol = 6.1mol
  3. S = 24.2g ÷ 32g/mol = 0.76mol
  4. O = 48.5g ÷ 16g/mol = 3.03mol

Next, we divide each mole value by the smallest value (0.76mol).

  1. N = 1.51mol ÷ 0.76 = 2
  2. H = 6.1mol ÷ 0.76 = 8.03
  3. S = 0.76mol ÷ 0.76 = 1
  4. O = 3.03mol ÷ 0.76 = 3.99

Approximately, the whole number ratio of N, H, S and O is 2:8:1:4. Therefore, the empirical formula is N2H8SO4.

Learn more about empirical formula at: https://brainly.com/question/11588623