Answer:
charge will be equal to [tex]2.03\times 10^{-5}C[/tex]
Explanation:
We have given mass of the particle m = 1.45 gram = 0.00145 kg
Acceleration due to gravity [tex]g=9.8m/sec^2[/tex]
Electric field E = 700 N/C
Electric force will be equal to [tex]F=qE[/tex], here q is charge and E is electric field
For particle to be stationary this force must be equal to force due to gravity , that is mg force
So qE = mg
[tex]q=\frac{mg}{E}=\frac{0.00145\times 9.8}{700}=2.03\times 10^{-5}C[/tex]
So charge will be equal to [tex]2.03\times 10^{-5}C[/tex]
The charge on the particle as described is; 2.03 ×10⁵C.
The given mass of the particle, m = 1.45 g = 0.00145 kg
Electric force on the particle is therefore given by;
where
For particle to be stationary this force must be equal to force due to gravity , that is mg force
Hence, qE = mg
The charge on particle is therefore; 2.03 ×10⁵C.
Read more on Charge on a particle;
https://brainly.com/question/1281551
