Answer:
0.79014 J
Explanation:
According to the first law of thermodynamics:-
[tex]\Delta U = q + w[/tex]
Where,
U is the internal energy
q is the heat
w is the work done
From the question,
q = 0 J
The expression for the calculation of work done is shown below as:
[tex]w=P\times \Delta V[/tex]
Where, P is the pressure
[tex]\Delta V[/tex] is the change in volume
From the question,
[tex]\Delta V[/tex] = 3 - 1 L = 2 L
P = 400 Pa
The expression for the conversion of pressure in Pascal to pressure in atm is shown below:
P (Pa) = [tex]\frac {1}{101325}[/tex] P (atm)
Given the value of pressure = 43,836 Pa
So,
400 Pa = [tex]\frac {400}{101325}[/tex] atm
Pressure = 0.0039 atm
[tex]w=0.0039\times 2\ atmL[/tex]
Also, 1 atmL = 101.3 J
So,
[tex]w=0.0039\times 2\times 101.3\ J=0.79014\ J[/tex] (work is done by the system)
So,
[tex]\Delta U = 0\ J+0.79014\ J =0.79014\ J[/tex]
