Answer:
Explanation:
Given
Two charges with charge [tex]Q=5\ \mu C[/tex]
When the first charge is at [tex]x=10\ cm[/tex] on the x-axis and another at x=0 (origin)
there is only Potential Energy
Total Energy(E)=Kinetic Energy(K)+Potential Energy(U)
[tex]U_i=\frac{kQ\cdot Q}{r}[/tex]
[tex]U_i=\frac{9\times 10^9\times (5\times 10^{-6})^2}{0.1}[/tex]
[tex]U_i=2.25\ J[/tex]
[tex]E=2.25[/tex]
When First charge is at [tex]x=90[/tex]
There will be both Kinetic energy and potential Energy
[tex]U_f=\frac{kQ\cdot Q}{r}[/tex]
[tex]U_f=\frac{9\times 10^9\times (5\times 10^{-6})^2}{0.9}[/tex]
[tex]U_f=0.25\ J[/tex]
As total Energy is constant therefore Kinetic Energy is
[tex]k=E-U_f[/tex]
[tex]k=2.25-0.25=2\ J[/tex]
