Answer:
ΔT' = 9.5 x C / C'
= 4.65°C
Step-by-step explanation:
To calculate the rise in temperature of B, we know that the heat released by Object A will be equal to the absorbed heat by object B
Hence:
Heat released by A = Heat absorbed by B
This means that C ΔT = C' ΔT'
But we are told that when brought into contact, A cools down by 9.5°C, hence we know that the change in temperature by object A is by 9.5°C
Hence:
C × 9.5 = C' ΔT'
If we make ΔT', which will imply the rise in temperature of B the subject of the formula, we get:
ΔT' = 9.5 x C / C'
From the question
C = 2.28J
C' = 4.66 J
Hence ΔT' = 9.5 x 2.28/4.66 = 4.65°C