Answer:
16 g/L
Explanation:
Given that:-
Mass of sucrose added = 1.2 g
Volume of water = 75 mL = 0.075 L ( 1mL = 0.001 L )
%w/v is defined as the mass of the solution in 1 L of the solution.
So,
[tex]\%\ w/v=\frac{Mass_{solute}}{Volume_{Solution}}[/tex]
[tex]\%\ w/v=\frac{1.2\ g}{0.075\ L}=16\ g/L[/tex]
