Answer:
3689 years
Explanation:
The amount of fossil = 64.0% compare to living organism = 0.64
The number of half life elapsed = [tex](\frac{1}{2})^n=0.64[/tex]
[tex](0.5)^n =0.64[/tex]
[tex]nlog0.5=log(0.64)[/tex]
[tex]\frac{-0.1938}{-0.30102}[/tex]
[tex]= 0.643811[/tex]
n= 0.6438
However, the age of the fossil = half life of C-14 × number of half life elapsed
= 5730 × 0.6438
= 3689 years
