Answer:
10.05volts
Explanation:
Work done to move a charge from the positive side of a plate to the negative side is represented mathematically as 1/2CV² which is also the energy stored by the capacitor.
Work done = 1/2CV² where
C is the charge
V is voltage difference that exists between the plates.
Given Work done = 101Joules
C = 2Coulombs
Substituting the values in the formula to get V, we will have;
101 = 1/2(2)V²
101 = V²
V = √101
V = 10.05volts
Therefore the voltage difference between the plates is 10.05colt's
