The modulus of elasticity is 28.6 X 10³ ksi
Explanation:
Given -
Length, l = 5in
Force, P = 8000lb
Area, A = 0.7in²
δ = 0.002in
Modulus of elasticity, E = ?
We know,
Modulus of elasticity, E = σ / ε
Where,
σ is normal stress
ε is normal strain
Normal stress can be calculated as:
σ = P/A
Where,
P is the force applied
A is the area of cross-section
By plugging in the values, we get
σ = [tex]\frac{8000 X 10^-^3}{0.7}[/tex]
σ = 11.43ksi
To calculate the normal strain we use the formula,
ε = δ / L
By plugging in the values we get,
ε = [tex]\frac{0.002}{5}[/tex]
ε = 0.0004 in/in
Therefore, modulus of elasticity would be:
[tex]E = \frac{11.43}{0.004} \\\\E = 28.6 X 10^3 ksi[/tex]
Thus, modulus of elasticity is 28.6 X 10³ ksi
