(b) Suppose oil spills from a ruptured tanker and spreads in a circular pattern. If the radius of the oil spill increases at a constant rate of 1 m/s, how fast is the area of the spill increasing when the radius is 26 m?

Respuesta :

Answer:

163.4 or [tex]52\pi[/tex] m2/s

Explanation:

The rate of change of the radius is 1 m/s

[tex]\dfrac{dr}{dt}=1[/tex]

The area of a circle is

[tex]A=\pi r^2[/tex]

We differentiate this to get the rate of change of the area with the radius:

[tex]\dfrac{dA}{dr}=2\pi r[/tex]

The rate of change of the area is

[tex]\dfrac{dA}{dt} = \dfrac{dA}{dr}\times\dfrac{dr}{dt}=2\pi r \times1 = 2\pi r[/tex]

At r = 26 m,

[tex]\dfrac{dA}{dt}=2\pi \times26=52\pi=163.4[/tex]

Explanation:

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