contestada

Write an equation that involves
multiplication, contains a variable, and
has a solution of 5. Then write another
equation that has the same solution and
includes the same variable and numbers
but uses division.

Respuesta :

so the solution is 5 we'll start with that

x=5

to do reverse multiplcation, you must divide so 

x=5

x/10=5/10

x/10=1/2

then the other problem

x=5

5x=25

to solvve

x/10=1/2

multiply by 10

x=5

then 

5x=25

divide both sides by 5

x=5

We can use any equation, as long as it’s solution is 5.

So, 4x(5+x)-2(5x+2x^2)=50

10x=50

x=5

Now, to use division:

20x/10+ 4x^2/4x^2=11

Simplifying we get:

2x+1=11

2x=10
x=5.

This is a little complicated, but I hope this helps!