Answer:
2.7 s
Explanation:
The period of the motion of a massless loaded spring is given by
[tex]T = 2\pi\sqrt{\dfrac{m}{k}}[/tex]
where m is the mass of the load and k is the force or spring constant.
Using values in the question and converting to appropriate units,
[tex]T = 2\pi\sqrt{\dfrac{927\times10^{-3}\text{ kg}}{5 \text{ N/m}}}= 2.7\text{ s}[/tex]
