Answer:
Terminal voltage = 11.5 V
Power across load = 119.7 W
Power across internal resistance = 5.4 W
Power delivered by battery = 125.2 W
Explanation:
The current in the circuit is given by
[tex]I=\dfrac{E}{R+r}[/tex]
where E is the emf of the battery, R us the load resistance and r is the internal resistance.
[tex]I=\dfrac{12}{1.1+0.05} = 10.43 \text{ A}[/tex]
The terminal voltage is the potential difference across the load resistor.
V = I × R = 10.43 A × 1.1 Ω = 11.5 V
The power across any resistance is given by [tex]I^2R[/tex]
For the load resistor,
[tex]P_L=10.43^2\times1.1 = 119.7 \text{ W}[/tex]
For the internal resistance,
[tex]P_r=10.43^2\times0.05= 5.4\text{ W}[/tex]
The power delivered by the battery is
[tex]P = P_L + P_r = 119.7 + 5.4 = 124.1 \text{ W}[/tex]
This could also be found by
[tex]P = IE = 10.34\times12 = 125.2 \text{ W}[/tex]
The discrepancy in both answers is due to the approximations. The second answer is better.
