Answer:
0.73
Step-by-step explanation:
Variance (V) = 25 days
Standard deviation (σ) = √V = √25 = 5 days
Mean path length (μ) = 30 days
Assuming a normal distribution, the z-score for any given path length, X, is given by:
[tex]z=\frac{X-\mu}{\sigma}[/tex]
For X = 33 days:
[tex]z = \frac{33-30}{5}=0.6[/tex]
A z-score of 0.6 corresponds to the 72.57th percentile of normal distribution.
Therefore, the probability that the project will be completed in 33 days or less is equal to:
[tex]P(X \leq 33) = 0.7257=0.73[/tex]