Answer:
The distance moved by the body in these 2 seconds is 22 meters.
Explanation:
Given that,
Initial velocity of a body, u = 6 m/s
Final velocity of the body, v = 16 m/s
Time, t = 2 s
Let d is the distance moved by the body in these 2 seconds is. Using third equation of motion to find it such that,
[tex]v^2-u^2=2ad\\\\(16)^2-(6)^2=2\times (\dfrac{16-6}{2})\times d\\\\d = 22\ m[/tex]
So, the distance moved by the body in these 2 seconds is 22 meters. Hence, this is the required solution.
