Consider the following equation. 9x2 − y2 = 6 (a) Find y' by implicit differentiation. y' = (b) Solve the equation explicitly for y and differentiate to get y' in terms of x. y' = ±

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Answer:

Step-by-step explanation:

Given is an equation in x and y as

[tex]9x^2 - y^2 = 6[/tex]

We use implicit method to differentiate the above equation

18x-2yy'=0

y' = 9x/y

b) to solve the equation explicitly for y and differentiate to get y' in terms of x. y' = ±

We separate the variables as

[tex]yy' =9x\\\frac{y^2}{2} =\frac{9x^2}{2} +C\\y^2 =9x^2+2C[/tex]

Take square root

[tex]y=\sqrt{9x^2+2C} \\y=-\sqrt{9x^2+2C}[/tex]

The value of y' by implicit differentiation is 9x/y and the value of y is [tex]\pm \sqrt{9x^2 + 2C}\\[/tex].

What is implicit differentiation?

We differentiate each side of an equation with two variables by taking one as a variable and the rest are constant.

Given

The function is [tex]\rm 9x^2 - y^2 = 6[/tex].

where x and y are variables.

a.  The function is [tex]\rm 9x^2 - y^2 = 6[/tex].

On differentiating the equation, we have

[tex]\rm 18x - y y' = 0\\[/tex]

on simplifying, we have

[tex]\rm y' = \dfrac{9x }{y}[/tex]

b.  To solve the equation explicitly for y and differentiate to get y' in terms of x.

[tex]\rm y' = \dfrac{9x }{y}[/tex]

Separate the variables

[tex]\rm yy' = 9x\\\\\dfrac{y^2}{2} = \dfrac{9x^2}{2} + C\\\\y^2 = \9x^2 + 2C[/tex]

Taking square root on both the side

[tex]\rm y = \pm \sqrt{9x^2 + 2C}\\[/tex]

More about the implicit differentiation link is given below.

https://brainly.com/question/20319481