Answer:
Step-by-step explanation:
C is a point (-4,2,5)
Plane is 2x+5y -4z =5 and the sphere with centre at C touches this plane.
Equation of C from this plane would be radius of the sphere.
Radius =
=[tex]|\frac{2(-4)+5(2)-4(5)-5}{\sqrt{2^2+5^2+4^2} } |\\=\frac{23}{\sqrt{45} }[/tex]
Centre is (-4,2,5)
If (x,y,z) is a general point in the sphere, distance between (x,y,z) and (-4,2,5) would equal radius.
i.e.
[tex](x+4)^2+(y-2)^2+(z-5)^2 = \frac{529}{45}[/tex]
is the sphere equation.
