An object has a weight W when it is on the surface of a planet of radius R. What will be the gravitational force on the object after it has been moved to a distance of 4R from the center of the planet?

Respuesta :

Answer:

W/16

Explanation:

The force of gravity, W = mg = GMm/R²

When R increases by a factor of four, W decreases by 4² or 16.

Answer:

Gravitational force on the object will be [tex]\frac{W}{16}[/tex]

Explanation:

Given information:

Radius of planet,

[tex]R_1=r\\R_2=4r[/tex]

[tex]F_1=W[/tex]

By Newton's law of universal gravitation,

[tex]F=G\times \frac{m_1m_2}{r^2}[/tex], here [tex]G[/tex] is gravitational constant,

On substitution,

[tex]\frac{F_1}{F_2}=\frac{{r_2}^2}{{r_1}^2}=\frac{(4r)^2}{r^2}=16[/tex]

[tex]\frac{F_1}{16}=F_2[/tex]

[tex]F_2=\frac{W}{16}[/tex]

Hence,Gravitational force on the object will be [tex]\frac{W}{16}[/tex].

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