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The components of a velocity field are given by u = x + y, and v = xy3 + 16 and w = 0. Determine the location of the stagnation point (V = 0) in the flow field where y is positive

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shadrachadamu

Answer:

Stagnation v(=0) occurs at (x,y) => (2, -2)

Explanation:

V = 0 provided both x and y are = 0

and also at stagnation V = U

V = xy³ + 16 = 0

xy³ = -16

x+y = 0 => x = -y

x(-x)³= -16

-x⁴ = -16

x⁴ = 16

x = 2.

Since x = -y it follows that y = -2.

Therefore, Stagnation v(=0) occurs at (x,y) => (2, -2)

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