Answer:
The Chain length is 67.5in
The allowable horsepower is 31.1hp
Explanation:
A)
p = 0.5in
Use the following relation to calculate the chain length
[tex]\frac{L}{P} =\frac{2C}{P} +\frac{N_{1} +N_{2}}{2}+\frac{[N_{2}-N_{1}]^{2}}{4\pi^{2} (C/P)}[/tex] ......................(1)
C (20in) is center to center distance, N₁ (21) is number of driving teeth, N₂ (84) is number of driven teeth.
Substitute the above values in equation (1)
L = 135 x 0.5
= 67.5in
B)
[tex]K_1 = [\frac{N_1}{17}]^{1.5}[/tex]
Substitute 21 for N₁
K₁ = 1.37
Multiple strand factors in the text book for 4 strands K₂ = 3.3
The allowable horsepower
[tex]H_a = K_1 * K_2 * H_{tab}[/tex]
Hₐ = 1.37 x 3.3 x 6.88
= 31.1 hp