A four-strand no. 40 roller chain transmits power from a 21-tooth driving sprocket to an 84-tooth driven sprocket. The angular speed of the driving sprocket is 2000 rev/min. A life of 20 000 hours is desired.
(a) Estimate the chain length if the center-to-center distance has to be about 20 in.
(b) Estimate the allowable horsepower for a 20 000-h life.

Respuesta :

Answer:

The Chain length is 67.5in

The allowable horsepower is 31.1hp

Explanation:

A)

p = 0.5in

Use the following relation to calculate the chain length

[tex]\frac{L}{P} =\frac{2C}{P} +\frac{N_{1} +N_{2}}{2}+\frac{[N_{2}-N_{1}]^{2}}{4\pi^{2} (C/P)}[/tex]  ......................(1)

C (20in) is center to center distance, N₁ (21) is number of driving teeth, N₂ (84) is number of driven teeth.

Substitute the above values in equation (1)

L = 135 x 0.5

  = 67.5in

B)

[tex]K_1 = [\frac{N_1}{17}]^{1.5}[/tex]

Substitute 21 for N₁

K₁ = 1.37

Multiple strand factors in the text book for 4 strands K₂ = 3.3

The allowable horsepower

[tex]H_a = K_1 * K_2 * H_{tab}[/tex]

Hₐ = 1.37 x 3.3 x 6.88

    = 31.1 hp