Answer: The equilibrium constant for the overall reaction is [tex]K_1\times (K_2)^2[/tex]
Explanation:
The given chemical equations follows:
Equation 1: [tex]4NH_3(g)+5O_2(g)\xrightarrow[]{K_1} 4NO(g)+6H_2O(g)[/tex]
Equation 2: [tex]2NO(g)+O_2(g)\xrightarrow[]{K_2} 2NO_2(g)[/tex] ( × 2)
The net equation follows:
[tex]4NH_3(g)+7O_2(g)\xrightarrow[]{K} 4NO_2(g)+6H_2O(g)[/tex]
The equilibrium constant for the net reaction will be the multiplication of two above equations.
If the equation is multiplied by a factor of '2', the equilibrium constant of the net reaction will be the square of the equilibrium constant of respective reaction.
The value of equilibrium constant for net reaction is:
[tex]K=K_1\times (K_2)^2[/tex]
Hence, the equilibrium constant for the overall reaction is [tex]K_1\times (K_2)^2[/tex]