3.00 mL of 0.00200 M Fe3+ is mixed with 4.00 mL of 0.00200 M SCN– and 3.00 mL of H2O? What is the initial concentration of Fe3+ after mixing, but before any reaction takes place?

Respuesta :

Answer : The concentration of [tex]Fe^{3+}[/tex] after mixing is, [tex]6.0\times 10^{-4}M[/tex]

Explanation :

First we have to calculate the moles of [tex]Fe^{3+}[/tex] before mixing.

[tex]\text{Moles of }Fe^{3+}=\text{Concentration of }Fe^{3+}\times \text{Volume of }Fe^{3+}[/tex]

[tex]\text{Moles of }Fe^{3+}=0.00200M\times 0.003L=6.0\times 10^{-6}mol[/tex]

Now we have to calculate the total volume of solution after mixing.

Volume of solution = (3.00 + 4.00 + 3.00) mL

Volume of solution = 10.00 mL = 0.010 L

Now we have to calculate the concentration of [tex]Fe^{3+}[/tex] after mixing.

[tex]\text{Concentration of }Fe^{3+}=\frac{\text{Moles of }Fe^{3+}}{\text{Volume of solution}}[/tex]

[tex]\text{Concentration of }Fe^{3+}=\frac{6.0\times 10^{-6}mol}{0.010L}=6.0\times 10^{-4}M[/tex]

Thus, the concentration of [tex]Fe^{3+}[/tex] after mixing is, [tex]6.0\times 10^{-4}M[/tex]