Answer:
239K
Explanation:
Data obtained from the question is given below:
V1 = 0.250L
T1 =?
T2 = 306K
V2 = 0.320L
Now, we can easily find the starting temperature by doing the following:
V1 /T1 = V2/T2
0.250/ T1 = 0.320/306
Cross multiply to express in linear form
T1 x 0.320 = 0.250 x 306
Divide both side 0.320
T1 = (0.250 x 306) / 0.320
T1 = 239K
