contestada

Jake walks 4m due north and then 3m due west to take a walk. The distance that jake walks is ___ m

Respuesta :

Answer:

5m

Explanation:

Let x be the distance that Jake walked,

(4²+3²)=x²

25=x²

x=5m

The distance that Jake walks is 5 meters.

Both north and west directions are orthogonal to each other, that is, perpendicular to each other. Hence, we can determine the resulting distance by means of the Pythagorean Theorem:

[tex]r = \sqrt{x^{2}+y^{2}}[/tex] (1)

Where:

  • [tex]r[/tex] - Resulting distance, in meters.
  • [tex]x[/tex] - Distance to the west, in meters.
  • [tex]y[/tex] - Distance to the north, in meters.

If we know that [tex]x = 3\,m[/tex] and [tex]y = 4\,m[/tex], then the resulting distance is:

[tex]r = \sqrt{(3\,m)^{2}+(4\,m)^{2}}[/tex]

[tex]r = 5\,m[/tex]

The distance that Jake walks is 5 meters.

We kindly invite to check this question on distances: https://brainly.com/question/21599807

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