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A sealed container holding 0.0255 L of an ideal gas at 0.979 atm and 67 ∘ C is placed into a refrigerator and cooled to 41 ∘ C with no change in volume. Calculate the final pressure of the gas. P = atm

Respuesta :

Answer:

[tex]0.904 atm[/tex]

Explanation:

Using Gay Lusaac's law where there is no change in Volume. The pressure changes directly proportional to absolute T°

P₁/T₁ = P₂/T₂

P₁T₂/T₁

P₂ = [tex]\frac{0.979 atm * 314k }{340k}[/tex]

P₂ = [tex]0.904 atm[/tex]

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