Answer:
0.07789 M is the sodium hydroxide concentration.
Explanation:
Mass of potassium hydrogen phthalate = 0.6986 g
Molar mass of potassium hydrogen phthalate = 204.22 g/mol
Moles of potassium hydrogen phthalate = [tex]\frac{0.6986 g}{204.22 g/mol}=0.003421 mol[/tex]
[tex]NaOH+KHP\rightarrow NaKP+H_2O[/tex]
According to reaction , 1 mole og KHp reactswith 1 mole of NaOH , then 0.003421 moles of KHp will react with :
[tex]\frac{1}{1}\times 0.003421 mol=0.003421 mol[/tex]
Moles of NaOH = 0.003421 mole
Volume of NaOH solution = 43.92 ml = 0.04392 L ( 1 mL = 0.001L)
[tex]Concentration=\frac{Moles}{Volume(L)}[/tex]
Concentration of NaOH :
[tex]\frac{0.003421 mol}{0.04392 L}=0.07789 M[/tex]
0.07789 M is the sodium hydroxide concentration.
