Respuesta :
Answer:
1. In CH₄ molecule:
The oxidation number of H = (+ 1)
The oxidation number of C = (- 4)
2. In SO₂ molecule:
The oxidation number of O = (- 2)
the oxidation number of S = (+ 4)
3. In BF₃ molecule:
The oxidation number of F = (- 1)
the oxidation number of B = (+ 3)
Explanation:
Oxidation number represents the oxidation state of an element in a given chemical compound, which can be zero, negative or positive.
The overall charge on a given chemical molecule is equal to sum of the oxidation numbers of all the elements in that molecule.
Now, calculating the oxidation number-
1. In CH₄ molecule:
As we know, the oxidation number of H = (+ 1)
and the overall charge on the molecule = 0
Let the oxidation number of C be x
∴ x + (+ 1) × 4 = 0
⇒ x = (- 4)
Therefore, the oxidation number of C = (- 4)
2. In SO₂ molecule:
As we know, the oxidation number of O = (- 2)
and the overall charge on the molecule = 0
Let the oxidation number of S be x
∴ x + (- 2) × 2 = 0
⇒ x = (+ 4)
Therefore, the oxidation number of S = (+ 4)
3. In BF₃ molecule:
As we know, the oxidation number of F = (- 1)
and the overall charge on the molecule = 0
Let the oxidation number of B be x
∴ x + (- 1) × 3 = 0
⇒ x = (+ 3)
Therefore, the oxidation number of B = (+ 3)
