Respuesta :
Answer:
The predicted F2 genotype proportions are 1:1:1:1
Explanation:
Available data:
- e causes ebony
- ro causes rough eyes
- e and ro are recessive mutations
A- Cross a true-breeding strain of ebony flies (e e, ++) with a true-breeding strain of rough-eyed flies (++, ro ro)
Parental) e e , + + x + + , ro ro
Gametes) e+ e+ e+ e+ +ro +ro +ro +ro
Punnet square) e+ e+ e+ e+
+ro +e+ro +e+ro +e+ro +e+ro
+ro +e+ro +e+ro +e+ro +e+ro
+ro +e+ro +e+ro +e+ro +e+ro
+ro +e+ro +e+ro +e+ro +e+ro
F1) 100% +e+ro
B- Cross the F1 to a true-breeding strain with ebony body and rough eyes.
Parental) +e,+ro x ee, roro
Gametes) ++ ro+ e+ ero ero ero ero ero
Punnet square) ++ +ro e+ ero
ero +e+ro +eroro ee+ro eeroro
ero +e+ro +eroro ee+ro eeroro
ero +e+ro +eroro ee+ro eeroro
ero +e+ro +eroro ee+ro eeroro
F2) 4/16=1/4 +e,+ro
4/16=1/4 +e,roro
4/16=1/4 ee,+ro
4/16=1/4 ee,roro
The predicted F2 genotype proportions are 1:1:1:1
You can also calculate it by making the punnet square for each gene and then multipling the genotypic proportions, like this:
Parental) e + x e e + ro x ro ro
Gametes) e + e e + ro ro ro
Punnet Squares) e + ro +
e ee +e ro roro +ro
e ee +e ro roro +ro
F1) 1/2 ee F1) 1/2 +ro
1/2 +e 1/2 roro
F2 genotype proportions)
+e,+ro = 1/2 +e x 1/2 +ro= 1/4 +e,+ro
+e,roro= 1/2 +e x 1/2 roro= 1/4 +e,roro
ee,+ro= 1/2 ee x 1/2 +ro= 1/4 ee,+ro
ee,roro= 1/2 ee x 1/2 roro= 1/4 ee,roro