Answer:
Frequency is [tex]213.04\ s^{-1}.[/tex]
Explanation:
Distance between source 1 from the receiver , [tex]S_1 =\sqrt{10^2+22^2}=24.17\ m.[/tex]
Distance between source 2 from the receiver , [tex]S_2=\sqrt{5^2+22^2}=22.56\ m.[/tex]
Now ,
Path difference , [tex]r = S_1-S_2=24.17-22.56=1.61\ m.[/tex]
We know, for constructive interference path difference should be integral multiple of wavelength .
Therefore, [tex]r=n\times \lambda[/tex]
It is given that n = 1,
Therefore, [tex]\lambda=1.61\ m.[/tex]
Frequency can be found by , [tex]\nu=\dfrac{v}{\lambda}= \dfrac{343}{1.61}= 213.04\ s^{-1} .[/tex]
Hence, this is the required solution.
