Answer:
The work done by the crane on the beam is [tex]5.66\times 10^5\ J[/tex].
Explanation:
Given that,
Mass of the steel beam, m = 425 kg
Acceleration of the beam in upward direction, [tex]a=1.8\ m/s^2[/tex]
Let the distance covered by the crane is 117 m, d = 117 m
We need to find the work done by the crane on the beam. The net force acting on the crane is given by :
[tex]F=m(g+a)[/tex]
Let W is the work done. It is given by :
[tex]W=m(g+a)\times d[/tex]
[tex]W=425\times (9.8+1.8)\times 115\\\\W =5.66\times 10^5\ J[/tex]
So, the work done by the crane on the beam is [tex]5.66\times 10^5\ J[/tex]. Hence, this is the required solution.
