Answer:
Therefore,
The Total current drawn is 20.83 Ampere.
Explanation:
Given:
Voltage, V = 120 V
Power of Appliances,
P1 = 1200-W Hair dryer,
P2 = 800-W Curling iron,
P3 = 500-W Light
To Find:
Current flowing in the line, I = ?
Solution:
We have Power formula,
[tex]Power = Voltage\times Current\\P=V\times I[/tex]
Current for hair dryer,
[tex]P_{1}=V\times I_{1}[/tex]
Substituting the values we get
[tex]1200=120\times I_{1}\\I_{1}=\dfrac{1200}{120}=10\ Ampere[/tex]
Similarly for curling iron,
[tex]P_{2}=V\times I_{2}[/tex]
[tex]800=120\times I_{2}\\I_{2}=\dfrac{800}{120}=6.6667\ Ampere[/tex]
Similarly for electric light
[tex]P_{3}=V\times I_{3}[/tex]
[tex]500=120\times I_{3}\\I_{3}=\dfrac{500}{120}=4.1667\ Ampere[/tex]
As all three of these appliances are operating in parallel on a 120-V circuit, the total current will be given as
[tex]I=I_{1}+I_{2}+I_{3}[/tex]
Substituting the values we get
[tex]I=10+6.6667+4.1667=20.8334\approx 20.83\ Ampere[/tex]
Therefore,
The Total current drawn is 20.83 Ampere.
