Respuesta :
Answer:
(a)15,543,360,000 cubic feet
(b)0.86%
Step-by-step explanation:
The dam contains approximately 1,800,000,000,000 cubic feet of water.
Water was released at a rate of 25,700 cubic feet per second
Since this is done for a week, we determine first the number of seconds in a week.
1 week =(7 X 24 X 60 X 60 ) seconds = 604,800 seconds
(a) Total Volume of Water Released During the Week
= 25700 X 604800 =15,543,360,000 cubic feet
(b)Percentage of the Dam Released
[tex]\frac{Volume of water released}{Total dam volume}[/tex]=
[tex]\dfrac{15543360000}{1800000000000} X 100=0.86\%[/tex]
Answer:
A) Volume of water released for the 1 week= =15,543,360,000 ft³
B) Percentage of water released for the 1 week = 0.864%
Step-by-step explanation:
From the question, we are given;Water contained by dam= 1,800,000,000,000 ft³
Rate at which water was released =25,700 ft³/s
Time for which water was released at that rate = 1 week.
Now, we have to convert this 1 week to seconds since the rate is in m³/s
Thus, 1 week = 7days/week x 24 hours/day x 60minutes/hour x 60 seconds/minute = 604,800 seconds
A) So, total volume of water released for this 1 week duration is;
= 25700 X 604800 =15,543,360,000 ft³
B) Percentage released = [(Volume of water released for the week)/(Volume of water contained in dam)] x 100% = (15,543,360,000/1,800,000,000,000) x 100%= 0.864%
