Answer:
335.994
Explanation:
Let consider that volume inside tire remains constant and air behaves as an ideal gas. No leakage exist (number of moles remains constant). The final pressure is calculated by the following formula:
[tex]P_{2} = P_{1} \cdot (\frac{T_{2}}{T_{1}} )\\P_{2} = 310\, kPa \cdot (\frac{323.15\, K}{298.15 \, K} )\\P_{2} = 335.994\,kPa[/tex]