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A particle that has a charge of 6.0 μC moves with a velocity of magnitude 5 × 105 m/s along the +x axis. It experiences no magnetic force, although there is a magnetic field present. The maximum possible magnetic force that the charge with the given speed could experience has a magnitude of 0.380 N. Find the magnitude and direction of the magnetic field. Note that there are two possible answers for the direction of the field.

Respuesta :

Answer:

[tex]B= 0.127\ T[/tex] and possible directions are +x axis and -x axis .  

Explanation:

Given :

Charge , [tex]q=6\ \mu C=6\times 10^{-6}\ \mu C.[/tex]

Velocity , [tex]v=5 \times 10^5 \ m/s[/tex].

Maximum possible magnetic force , [tex]F=0.380\ N.[/tex]

We know, Maximum force

[tex]F=qvB\\\\B=\dfrac{F}{qv}[/tex]

Putting all values we get ,

[tex]B= 0.127\ T.[/tex]

Now , it is given that no force is applied in the charge .

Therefore, magnetic field must be parallel to it.

It can only happen in two ways , when field is along +x axis or -x axis .

Hence, this is the required solution.

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