Respuesta :
Answer:
For A: The molarity of sucrose solution is 0.102 M
For B: The volume of water that would be added to the solution is 2 liters
Explanation:
- For A:
To calculate the molarity of solution, we use the equation:
[tex]\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}[/tex]
Given mass of sucrose = 35.0 g
Molar mass of sucrose = 342.3 g/mol
Volume of solution = 1.000 L
Putting values in above equation, we get:
[tex]\text{Molarity of solution}=\frac{35}{342.3\times 1}\\\\\text{Molarity of solution}=0.102M[/tex]
Hence, the molarity of sucrose solution is 0.102 M
- For B:
To calculate the volume of the diluted solution, we use the equation:
[tex]M_1V_1=M_2V_2[/tex]
where,
[tex]M_1\text{ and }V_1[/tex] are the molarity and volume of the concentrated sucrose solution
[tex]M_2\text{ and }V_2[/tex] are the molarity and volume of diluted sucrose solution
We are given:
[tex]M_1=0.102M\\V_1=1L\\M_2=\frac{0.102}{2}=0.051M\\V_2=?L[/tex]
Putting values in above equation, we get:
[tex]0.102\times 1=0.051\times V_2\\\\V_2=\frac{0.102\times 1}{0.051}=2L[/tex]
Hence, the volume of water that would be added to the solution is 2 liters
