Respuesta :
Answer: The equilibrium concentration of chlorine gas, fluorine gas and ClF gas is 0.159 M, 0.317 M and 1.002 M respectively.
Explanation:
We are given:
Initial concentration of chlorine gas = 0.307 M
Initial concentration of fluorine gas = 0.465 M
Initial concentration of ClF gas = 0.706 M
The given chemical equation follows:
[tex]Cl_2(g)+F_2(g)\rightleftharpoons 2ClF(g)[/tex]
Initial: 0.307 0.465 0.706
At eqllm: 0.307-x 0.465-x 0.706+2x
The expression of [tex]K_c[/tex] for above equation follows:
[tex]K_c=\frac{[ClF]^2}{[Cl_2][F_2]}[/tex]
We are given:
[tex]K_c=20.0[/tex]
Putting values in above equation, we get:
[tex]20.0=\frac{(0.706+2x)^2}{(0.307-x)(0.465-x)}\\\\x=0.148,0.993[/tex]
Neglecting the value of x = 0.993 because the equilibrium concentrations of chlorine and fluorine gases will become negative, which is not possible
So, equilibrium concentration of chlorine gas = (0.307 - x) = [0.307 - 0.148] = 0.159 M
Equilibrium concentration of fluorine gas = (0.465 - x) = [0.465 - 0.148] = 0.317 M
Equilibrium concentration of ClF gas = (0.706 + 2x) = [0.706 + 2(0.148)] = 1.002 M
Hence, the equilibrium concentration of chlorine gas, fluorine gas and ClF gas is 0.159 M, 0.317 M and 1.002 M respectively.
The equilibrium concentration of Chlorine is 0.159 M, Fluorine is 0.317 M, and ClF is 1.002 M.
According to the given chemical equation,1 mole of chlorine reacts with 1 mole of fluorine to give 2 moles of chlorine fluoride.
The initial concentration of Chlorine = 0.307 M
Fluorine = 0.465 M
Chlorine fluoride = 0.706 M.
After equilibrium, the formation of ClF will be 0.706 + 2x
Fluorine = 0.465 - x
Chlorine = 0.307 - x
The expression of [tex]\rm K_c[/tex] = [tex]\rm \dfrac{[ClF]^2}{[Cl_2]\;[F_2]}[/tex]
The expression of [tex]\rm K_c[/tex] = [tex]\rm \dfrac{(0.706\;+\;2x)^2}{(0.307\;-\;x)\;(0.465\;-\;x)}[/tex]
20 = [tex]\rm \dfrac{(0.706\;+\;2x)^2}{(0.307\;-\;x)\;(0.465\;-\;x)}[/tex]
x = 0.148
The concentration of ClF will be 0.706 + 2x = 0.706 + 2(0.148)
The concentration of ClF = 1.002 M
The concentration of Fluorine = 0.465 - 0.148
The concentration of Fluorine = 0.317 M
The concentration of Chlorine = 0.307 - 0.148
The concentration of Chlorine = 0.159 M.
For more information about the equilibrium concentration, refer to the link:
https://brainly.com/question/16645766
