Answer:
a) T = ln2/ln[(100+r)/100]
b) 10.2 years (3 sf)
c) 9.05% (3 sf)
Step-by-step explanation:
r% return: amount is (100+r)%
S = S0 × [(100+r)/100]^T
S = 2S0
2S0 = S0×[(100+r)/100]^T
2 = [(100+r)/100]^T
ln(2) = T ln[(100+r)/100]
T = ln2/ln[(100+r)/100]
b) r = 7
T = ln2/ln[(100+7)/100]
T = ln2/ln1.07
T = 10.24476837 years
T = 10.2 years (3 sf)
c) T = 8
8 = ln2/ln[(100+r)/100]
ln[(100+r)/100] = ln2/8
1 + r/100 = 1.090507733
r/100 = 0.090507733
r = 9.0507733%
r = 9.05% (3 sf)