Answer:
891.77 feet
Step-by-step explanation:
since it is not stated, i'm going to assume that 1200 feet is the actual distance the plane travels along the 48° elevation. (i.e its the hypotenuse)
(see attached sketch)
we can see that the elements of the diagram form a right triangle, this means that we can use trigonometry to solve for the elevation x,
sin (48°) = x / 1,200
x = 1,200 sin (48°)
x = 891.77 feet
The airplane is approximately 891.8 ft above the ground
The situation can be modelled with a right angle triangle. The airplane has been travelling for 1200 ft. The angle of elevation is 48°.
How far above the ground is the height of the right angle triangle. Therefore
using trigonometric ratio one can find the height.
hypotenuse = 1200 ft
angle = 48°
height = ?
sin 48 = opposite / hypotenuse
sin 48° = h / 1200
cross multiply
1200 sin 48 = h
h = 891.773790573
h ≈ 891.8 ft
Therefore, the airplane is approximately 891.8 ft above the ground
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