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When the following reaction is completed and written in the form of a net ionic equation, which of the following elements will NOT be present in the equation?

Pb(NO3)2(aq) + K2SO4(aq)

a. Pb
b. S
c. O
d. N

Respuesta :

Neetoo

Answer:

d. N

Explanation:

Chemical equation:

Pb(NO₃)₂(aq)  + K₂SO₄(aq)  →  PbSO₄(s) + KNO₃(aq)

Balanced Chemical equation:

Pb(NO₃)₂(aq)  + K₂SO₄(aq)  → PbSO₄(s) + 2KNO₃(aq)

Ionic equation:

Pb²⁺(aq) + 2NO₃⁻(aq)  + 2K⁺(aq) + SO₄²⁻(aq)  → PbSO₄(s) + 2K⁺(aq) + 2NO₃⁻(aq)

Net ionic equation:

Pb²⁺(aq) + SO₄²⁻(aq)  → PbSO₄(s)

The NO₃⁻(aq) and K⁺(aq)are spectator ions that's why these are not written in net ionic equation. The PbSO₄ can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.  

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