Answer:
note:
solution is attached due to error in mathematical equation. please find the attachment
Answer:
a. v = 21 m/s
b. t = 3.75 secs
Step-by-step explanation:
The initial velocity when the ball was pushed along the inclined plane is 5 m/s .The distance function with respect to time is given as s(t) = 5t + 4t².
The velocity is the derivative of displacement with respect to time. Mathematically, v = ds/dt
we have to differentiate the function s(t) = 5t + 4t².
s(t) = 5t + 4t²
v(t) = 5 + 8t
replacing t = 2 secs in the velocity function
v(t) = 5 + 8(2)
v = 21 m/s
b. The time it take for the velocity to reach 35 m/s can be computed with the derived velocity formula
v(t) = 5 + 8t
35 = 5 + 8t
35 - 5 = 8t
30 = 8t
t = 30/8
t = 3.75 secs
