Vinegar contains carbon, hydrogen, and oxygen with percent masses of 40.01% C and 6.70% H. If the molar mass of vinegar is about 60 g/mol, what is its molecular formula

Respuesta :

Answer: The molecular formula will be [tex]C_2H_4O_2[/tex]

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C= 40.01 g

Mass of H = 6.70 g

Mass of O = 100-(40.01+ 6.70) = 53.29 g

Step 1 : convert given masses into moles.

Moles of C =[tex]\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{40.01g}{12g/mole}=3.33moles[/tex]

Moles of H =[tex]\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{6.70g}{1g/mole}=6.70moles[/tex]

Moles of O =[tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{53.29g}{16g/mole}=3.33moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = [tex]\frac{3.33}{3.33}=1[/tex]

For H = [tex]\frac{6.70}{3.33}=2[/tex]

For O =[tex]\frac{3.33}{3.33}=1[/tex]

The ratio of C : H: O= 1: 2: 1

Hence the empirical formula is [tex]CH_2O[/tex]

The empirical weight of [tex]CH_2O[/tex] = 1(12)+2(1)+1(16)= 30 g.

The molecular weight = 60 g/mole

Now we have to calculate the molecular formula.

[tex]n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{60}{30}=2[/tex]

The molecular formula will be=[tex]2\times CH_2O=C_2H_4O_2[/tex]

The molecular formula will be  C₂H₄O₂. This can be described using empiricial formula first.

Determination of molecular formula:

The mass of each element is equal to the percentage given.

Mass of C= 40.01 g

Mass of H = 6.70 g

Mass of O = 100-(40.01+ 6.70) = 53.29 g

Conversion of masses into moles:

Moles of C = 40.01 / 12 = 3.33 moles

Moles of H = 6.70 / 1 =  6.70 moles

Moles of O = 53.29 / 16 = 3.33 moles

Dividing each with lowest moles:

For C =  3.33 / 3.33 = 1

For H =  6.70/ 3.33 = 2

For O = 3.33/ 3.33 = 1

The ratio of C : H: O= 1: 2: 1

Hence, the empirical formula is CH₂O

The empirical weight of CH₂O = 1(12)+2(1)+1(16)= 30 g.

The molecular weight = 60 g/mole

For molecular formula:

n= Molecular weight / Equivalent weight

n= 60/30 = 2

The molecular formula will be= 2 * CH₂O = C₂H₄O₂

Find more information about Molecular formulas here:

brainly.com/question/1603500