A 12.9 cm long solenoid contains 789 turns and carries a current of 5.99 A . What is the strength of the magnetic field at the center of this solenoid

Respuesta :

Answer:

[tex]B= 0.0462T[/tex]

Explanation:

Given that;

the diameter = 12.9 cm long

radius = [tex]\frac{d}{2}[/tex] =[tex]\frac{12.9}{2}[/tex]

= 6.45 cm

= 0.0645 m

The expression for the strength of the magnetic field at the center of this solenoid can be given as:

[tex]B = \frac{U_oNI}{2R}[/tex]

[tex]B = \frac{1.26*10^{-6}*789*5.99}{2*0.0645}[/tex]

[tex]B= 0.046162[/tex]

[tex]B= 0.0462T[/tex]