Answer:
Answer is explained below:
Explanation:
There are 12 fractions performed in triplicate Bradford data.1 ml of Bradford reagent and 50μl of protein is taken and mixed in a test tube for total volume of 1.05ml.The value taken of Bradford assays by microplate agent are compared through standard curve. This standard curve is made by using specific amounts of protein within each Bradford and then calculated by linear equation of standard curve.
Linear equation for standard curve is Y=0.0245 x + 0.03605
For the 1st trial of E3 :
it can be written as 0.511 = 0.0245 x + 0.3605 + x→ = 6.14μg
For the 2nd trial of E3 :
it can be written as 0.489 = 0.0245 x + 0.3605 + x→ = 5.24μg
For the 3rd trial of E3 :
it can be written as 0.478 = 0.0245 x + 0.3605 + x→ = 4.80μg
standard derivation = √∑ | x - average|²
n-1
by putting values in derivation, we will get 0.683
and
Standard derivation = √?