Respuesta :
Explanation:
Given that,
Radius of the circular loop, r = 3.5 cm = 0.035 m
(a) During a 0.12-s time interval, the magnitude of the field increases uniformly from 0.2 T to 0.5 T. Due to the change in the magnetic field, an emf will induced in it. The magnitude of induced emf is given by :
[tex]\epsilon=-\dfrac{d(BA)}{dt}\\\\\epsilon=-\pi r^2\dfrac{B_f-B_i}{dt}\\\\\epsilon=-\pi (0.035)^2\dfrac{0.5-0.2}{0.12}\\\\\epsilon=-9.62\times 10^{-3}\ volts[/tex]
So, the magnitude of the emf induced in the loop during the time interval is [tex]9.62\times 10^{-3}\ V[/tex].
(b) The negative sign shows that the direction of induced emf in the loop is in anitclockwise direction.
a. The magnitude of the emf induced in the loop is [tex]-9.62 *10^-2[/tex] volts.
b. the direction of the induced current in the loop should be anitclockwise direction.
Calculation of the magnitude & direction:
Since
Radius of the circular loop, r = 3.5 cm = 0.035 m
a. The magnitude of the emf should be
[tex]= -d(BA)/dt\\\\= -\pi r^2Bf- Bi/dt\\\\= -\pi (0.035)^2 (0.5-0.2)/0.12\\\\= -9.62*10^-3 volts\\\\[/tex]
b. Here the negative sign represent the direction of the induced current should be anitclockwise direction.
Learn more direction here: https://brainly.com/question/14656453
