Answer:
[tex]T_{f}=227K[/tex]
Explanation:
Given data
Initial temperature of air Ti=300 K
Vf (final volume of air)=2Vi (initial volume of air )
To find
Final temperature
Solution
Since no energy is lost by thermal conduction during the process we categorize this process as an adiabatic one.Hence we apply;
[tex]T_{i}V_{i}^{Y-1}=T_{f}V_{f}^{Y-1}\\T_{f}=T_{i}(\frac{V_{i}}{V_{f}} )^{Y-1}\\[/tex]
Where air is predominantly a diatomic gas Y=1.4m
Substitute the given values
So
[tex]T_{f}=300K(\frac{V_{i}}{2V_{i}} )^{1.4-1}\\T_{f}=227K[/tex]
