Answer:
Work is done by the heart on the blood during this time is 0.04 J
Explanation:
Given :
Mass of blood pumped, m = 80 g = 0.08 kg
Initial speed of the blood, u = 0 m/s
Final speed of the blood, v = 1 m/s
Initial kinetic energy of blood is determine by the relation:
[tex]E_{1}=\frac{1}{2} m u^{2}[/tex]
Final kinetic energy of blood is determine by the relation:
[tex]E_{2}=\frac{1}{2} m v^{2}[/tex]
Applying work-energy theorem,
Work done = Change in kinetic energy
W = E₂ - E₁
[tex]W=\frac{1}{2} m (v^{2}-u^{2})[/tex]
Substitute the suitable values in the above equation.
[tex]W=\frac{1}{2}\times0.08\times (1^{2}-0^{2})[/tex]
W = 0.04 J