Answer:
Total work done is 2606.08 J.
Explanation:
Given :
Mass of box , m = 23 kg .
Force applied , F = 100 N .
Angle from horizon , [tex]\theta=39^o[/tex].
Coefficient of kinetic friction , [tex]\mu=0.16[/tex].
Distance travelled by box , d = 34 m .
Now ,
Total work done = work done by boy + work done by friction.
[tex]W=Fdcos\theta+f_sdcos\theta=Fd-\mu(mg) \\\\W=100\times cos39^o\times 34-0.16\times 23 \times 9.8 \\\\W=77.71\times 34-36.06=2606.08\ J.[/tex]
Hence , this is the required solution.
