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Problem 6.13 The point of this question is to compare rest energy and kinetic energy at high speeds. An alpha particle (a helium nucleus) is moving at a speed of 0.9998 times the speed of light. Its mass is 6.40 × 10-27 kg. (a) What is its rest energy?

Respuesta :

Answer: E = 5.76×10^-10 J

Explanation: rest energy formula is given below as

E = mc²

m = mass of object = 6.40×10^-27 kg

c = speed of light = 3×10^8 m/s

E = 6.40×10^-27 × (3×10^8)²

E = 6.40×10^-27 × 9×10^16

E = 57.6 ×10^-11

E = 5.76×10^-10 J

The rest energy is  5.76×10^-10 J

Calculation of rest energy:

Since n alpha particle (a helium nucleus) is moving at a speed of 0.9998 times the speed of light. Its mass is 6.40 × 10-27 kg.

E = mc²

Here

m = mass of object = 6.40×10^-27 kg

c = speed of light = 3×10^8 m/s

So,

E = 6.40×10^-27 × (3×10^8)²

E = 6.40×10^-27 × 9×10^16

E = 57.6 ×10^-11

E = 5.76×10^-10 J

Learn more about energy here: https://brainly.com/question/24470698

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